Well I just looked up the product specs from the manual.
https://www.foscam.com/Uploads/usermanual/FI9803P%20FI9900P%20FI9800P%20User%20Manual%20V3.7.5.pdfPower Supply: 12 Volts / 1 Amp
Power consumption: max 5 watts.
The formula is A * V = W
But we know what the draw is a max of 5 Watts and the Volts is a steady 12 V. Therefore the formula needs to be manipulated to be W / V = A.
This gives us 5 W/ 12 V = 0.4166 Amps.
This means that the power supply needs to put out at least 0.4166 Amps for the camera to work which is why the power supply needs to be rated for more than that which is 1 Amp.
Then to measure what you are getting at the camera you need to use an Amps meter with an induction clamp or put the multimeter in the circuit and and set it for measuring Amps. Then you would know if the camera was or not getting the 0.4166 Amps that it needs. But that is max Amps....which means that probably it only uses that much at night when the IR is turned on. We still don't know what the nominal power consumption is. But we can test the camera without the extension and measure the Amps to the compare to the camera running with the extension to see if there is a difference.
If that is over anyone's head...that is okay. Camera works now so nothing needs to be done. This is just an exercise in case anyone was interested in thinking it through. But again I'm not an electrical expert. Maybe I made a mistake somewhere. If anyone knows any better then please correct me.