If you take byte 4 and convert it to binary, you will see that the values is has assumed in the test, which are 24,25,26,27 then 40,41,42,43 and then 56,57,58, 59 are made of two parts: the first four bits are fixed (the big steps), and the last four are variable (the jitter).
So:
24 25 26 and 27 have the first four bits set at 0001
40 41 42 and 43 have the first four bits set at 0010
56 57 58 and 59 have the first four bits set at 0011
So, you have to add the first four bits of bit 4 to byte 3 to get a 12-bit number. Try to plot this 12-bit number and compare it to the hum graph.
The last four bits of byte 4 are something else, or are random noise. I don't know.